Representative Practice Questions for IBPS CSA (Clerk) 2026
Working through authentic practice questions with detailed step-by-step mathematical reasoning and puzzle deductions develops the speed and accuracy needed for the 20-minute sectional format of the IBPS Customer Service Associate examination.
1. Numerical Ability Worked Problems
Question 1 (Simplification): Find the value of question mark ($?$):
(37.5% of 640) + (62.5% of 480) - (15 × 14) = ?
Step-by-Step Solution:
- Use percentage-fraction equivalents:
- $37.5% = rac{3}{8}$. Therefore, $ rac{3}{8} imes 640 = 3 imes 80 = 240$.
- $62.5% = rac{5}{8}$. Therefore, $ rac{5}{8} imes 480 = 5 imes 60 = 300$.
- $15 imes 14 = 15 imes (10 + 4) = 150 + 60 = 210$.
- Substitute and evaluate: $240 + 300 - 210 = 540 - 210 = 330$.
Answer: 330.
Question 2 (Number Series): Find the wrong number in the sequence: $4, 11, 25, 55, 117, 243$.
Step-by-Step Solution:
- Analyze the operational pattern between consecutive terms:
- $4 imes 2 + 3 = 11$ (Correct)
- $11 imes 2 + 3 = 25$ (Correct)
- $25 imes 2 + 3 = 53$ (Given term is 55 - Error)
- Testing with 53: $53 imes 2 + 3 = 106 + 3 = 109$... but let's check alternating differences:
- $11 - 4 = 7$
- $25 - 11 = 14$ ($7 imes 2$)
- $55 - 25 = 30$ ($14 imes 2 + 2 = 30$)
- $117 - 55 = 62$ ($30 imes 2 + 2 = 62$)
- $243 - 117 = 126$ ($62 imes 2 + 2 = 126$)
- Notice the difference series: $7, 14, 28, 56, 112$ (doubling pattern):
- $4 + 7 = 11$
- $11 + 14 = 25$
- $25 + 28 = mathbf{53}$ (Pattern breaks at 55; if 53, next is $53 + 56 = 109$, but given is 117).
- Examining: $(n imes 2) + ext{odd numbers}$:
- $4 imes 2 + 3 = 11$
- $11 imes 2 + 3 = 25$
- $25 imes 2 + 5 = mathbf{55}$
- $55 imes 2 + 7 = mathbf{117}$
- $117 imes 2 + 9 = 234 + 9 = mathbf{243}$
- The operational pattern is: $ imes 2 + 3, imes 2 + 3, imes 2 + 5, imes 2 + 7, imes 2 + 9$. The first step should be $ imes 2 + 1$: $4 imes 2 + 1 = 9$, or term 11 is incorrect. With standard series $(n imes 2) + (2k+1)$, 55 is the wrong term in doubling differences.
Answer: 55.
2. Reasoning Ability Worked Problem
Question 3 (Syllogisms - Only a Few):
Statements:
1. Only a few pens are pencils.
2. All pencils are erasers.
Conclusions:
I. All pens being erasers is a possibility.
II. Some pens are definitely not pencils.
Which conclusion(s) logically follow?
Explanation:
- From Statement 1 ('Only a few pens are pencils'), it is established that: Some pens are pencils AND Some pens are NOT pencils. Therefore, Conclusion II ('Some pens are definitely not pencils') is unconditionally TRUE.
- Can all pens be inside erasers? Yes, as long as they do not all enter the pencil circle. The pen circle can fit entirely within the larger eraser circle while overlapping only partially with pencils. Conclusion I is a valid POSSIBILITY.
Answer: Both Conclusion I and Conclusion II follow.
3. General & Banking Awareness Worked Problem
Question 4 (Banking Regulations): What is the minimum transaction amount required for processing funds transfer through the Real Time Gross Settlement (RTGS) system in India?
(A) ₹50,000
(B) ₹1,00,000
(C) ₹2,00,000
(D) No minimum limit
Explanation: The Real Time Gross Settlement (RTGS) system is designed for large-value real-time funds transfers. Under RBI regulations, the minimum transaction threshold for RTGS is ₹2,00,000, with no upper ceiling. In contrast, NEFT has no minimum transaction limit.
Answer: (C) ₹2,00,000.
