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Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A ball is dropped from a height of \( 90\text{ m} \) on a horizontal floor. At each collision with the floor, the ball loses one tenth (\( 1/10 \)) of its speed. What is the maximum height reached by the ball after its second collision with the floor? (Take \( g = 9.8\text{ m s}^{-2} \))

  1. A
    \( 72.90\text{ m} \)
  2. B
    \( 65.61\text{ m} \)
  3. C
    \( 52.40\text{ m} \)
  4. D
    \( 59.05\text{ m} \)
View Answer & Solution

Correct answer · Option D

\( 59.05\text{ m} \)

Explanation

Speed after each bounce becomes \( 0.9 \) of impact speed, so height becomes \( (0.9)^2 = 0.81 \) times previous height. After 2 bounces, \( H_2 = (0.81)^2 H_0 = 0.6561 \times 90\text{ m} = 59.049\text{ m} \approx 59.05\text{ m} \).
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