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Physics · PYQ NEET UG 2022
हिन्दीA ball is projected with a velocity, \( 10\text{ ms}^{-1} \), at an angle of \( 60^\circ \) with the vertical direction. Its speed at the highest point of its trajectory will be:
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Correct answer · Option D
\( 5\sqrt{3}\text{ ms}^{-1} \)
Explanation
Angle with horizontal \( \theta = 90^\circ - 60^\circ = 30^\circ \). Speed at highest point is \( v = u\cos(30^\circ) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}\text{ ms}^{-1} \).
