Physics · JEE | Magnetism and Matter
हिन्दीA bar magnet of magnetic moment \( 1.5\text{ J T}^{-1} \) lies aligned with the direction of a uniform magnetic field of \( 0.22\text{ T} \). What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment normal to the field direction?
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Correct answer · Option D
\( 0.33\text{ J} \)
Explanation
Work done \( W = mB(\cos\theta_1 - \cos\theta_2) = 1.5 \times 0.22 \times (\cos 0^\circ - \cos 90^\circ) = 0.33 \times (1 - 0) = 0.33\text{ J} \).