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Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A body moving with uniform acceleration along a straight path covers a distance of \( 40\text{ m} \) in \( 4\text{ s} \). If its velocity at the end of this interval is \( 15\text{ m s}^{-1} \), what was its initial velocity \( v_0 \)?

  1. A
    \( 10\text{ m s}^{-1} \)
  2. B
    \( 2.5\text{ m s}^{-1} \)
  3. C
    \( 5.0\text{ m s}^{-1} \)
  4. D
    \( 7.5\text{ m s}^{-1} \)
View Answer & Solution

Correct answer · Option C

\( 5.0\text{ m s}^{-1} \)

Explanation

Using \( x = (\frac{v + v_0}{2}) t \), we have \( 40 = (\frac{15 + v_0}{2}) \times 4 \implies 20 = 15 + v_0 \implies v_0 = 5.0\text{ m s}^{-1} \).
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