OnlineCBT Logo OnlineCBT

Physics · WORK, ENERGY AND POWER

हिन्दी

A body of mass \( m_1 \) moving with initial velocity \( v_{1i} \) collides head-on completely inelastically with a stationary body of mass \( m_2 \). The fraction of initial kinetic energy lost in the collision is:

  1. A
    \( \frac{m_2}{m_1 + m_2} \)
  2. B
    \( \frac{m_1 m_2}{(m_1 + m_2)^2} \)
  3. C
    \( \frac{m_1}{m_1 + m_2} \)
  4. D
    \( \frac{m_1 - m_2}{m_1 + m_2} \)
View Answer & Solution

Correct answer · Option A

\( \frac{m_2}{m_1 + m_2} \)

Explanation

Loss in kinetic energy is \( \Delta K = \frac{1}{2}\frac{m_1 m_2}{m_1 + m_2} v_{1i}^2 \). Initial KE is \( K_i = \frac{1}{2}m_1 v_{1i}^2 \). Fraction lost is \( \frac{\Delta K}{K_i} = \frac{m_2}{m_1 + m_2} \).
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat