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Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A bullet entering a wooden block with an initial velocity of \( 100\text{ m s}^{-1} \) comes to rest after penetrating a distance of \( 0.1\text{ m} \). Assuming uniform retardation, what is the magnitude of the deceleration of the bullet?

  1. A
    \( 5 \times 10^3\text{ m s}^{-2} \)
  2. B
    \( 1 \times 10^5\text{ m s}^{-2} \)
  3. C
    \( 2.5 \times 10^4\text{ m s}^{-2} \)
  4. D
    \( 5 \times 10^4\text{ m s}^{-2} \)
View Answer & Solution

Correct answer · Option D

\( 5 \times 10^4\text{ m s}^{-2} \)

Explanation

Using \( v^2 = v_0^2 + 2ax \), we get \( 0 = (100)^2 + 2a(0.1) \implies 0.2a = -10000 \implies a = -50000\text{ m s}^{-2} \). Magnitude of deceleration = \( 5 \times 10^4\text{ m s}^{-2} \).
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