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Physics · Electrostatic Potential

हिन्दी

A capacitor of capacitance \( C_1 = 4\, \mu\text{F} \) is charged to \( 50\text{ V} \) and another capacitor \( C_2 = 6\, \mu\text{F} \) is charged to \( 100\text{ V} \). If they are connected together in parallel with plates of like polarity connected together, the final common potential difference across the combination is:

  1. A
    \( 60\text{ V} \)
  2. B
    \( 80\text{ V} \)
  3. C
    \( 70\text{ V} \)
  4. D
    \( 75\text{ V} \)
View Answer & Solution

Correct answer · Option B

\( 80\text{ V} \)

Explanation

Common potential \( V_{\text{common}} = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2} = \frac{4 \times 50 + 6 \times 100}{4 + 6} = \frac{200 + 600}{10} = 80\text{ V} \).
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