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Physics · MECHANICAL PROPERTIES OF FLUIDS
हिन्दीA capillary tube of radius \( a = 0.5\text{ mm} \) is dipped in water of surface tension \( S = 0.075\text{ N/m} \) and density \( \rho = 1000\text{ kg/m}^3 \). If the contact angle is \( 0^\circ \) and \( g = 10\text{ m/s}^2 \), the capillary rise \( h \) is:
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Correct answer · Option D
\( 3.0\text{ cm} \)
Explanation
Capillary rise formula: \( h = \frac{2S\cos\theta}{\rho g a} = \frac{2 \times 0.075 \times 1}{1000 \times 10 \times 0.5 \times 10^{-3}} = \frac{0.15}{5} = 0.03\text{ m} = 3.0\text{ cm} \).
