OnlineCBT Logo OnlineCBT

Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

हिन्दी

A child stands at the centre of a turntable with outstretched arms rotating with an initial rotational kinetic energy \( K_0 \). When the child folds their arms, the moment of inertia of the system reduces to \( \frac{2}{5} \) of its initial value. Assuming no external torque acts, the ratio of the new rotational kinetic energy to the initial rotational kinetic energy (\( K_f / K_0 \)) is:

  1. A
    \( 2/5 \)
  2. B
    \( 5/2 \)
  3. C
    \( 4/25 \)
  4. D
    \( 25/4 \)
View Answer & Solution

Correct answer · Option B

\( 5/2 \)

Explanation

By conservation of angular momentum \( L = I\omega = \text{constant} \). Kinetic energy \( K = \frac{L^2}{2I} \). Therefore, \( \frac{K_f}{K_0} = \frac{I_0}{I_f} = \frac{1}{2/5} = \frac{5}{2} \).
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat