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Physics · JEE | Moving Charges and Magnetism
हिन्दीA circular loop of radius \( R \) carrying current \( I \) has magnetic field \( B_0 \) at its center. The magnetic field on the axis at a distance \( R \) from the center is:
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Correct answer · Option D
\( \frac{B_0}{2 \sqrt{2}} \)
Explanation
Magnetic field on axis is \( B = \frac{\mu_0 I R^2}{2(x^2 + R^2)^{3/2}} \). For \( x = R \), \( B = \frac{\mu_0 I}{2R(2)^{3/2}} = \frac{B_0}{2\sqrt{2}} \).
