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Physics · MOTION IN A PLANE
हिन्दीA cricket ball is thrown with a speed of \( 28\text{ m/s} \) at an angle of \( 30^\circ \) above the horizontal. Taking \( g = 9.8\text{ m/s}^2 \), the maximum height achieved by the ball is:
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Correct answer · Option D
10.0 m
Explanation
\( h_m = \frac{(v_o\sin\theta_o)^2}{2g} = \frac{(28 \sin 30^\circ)^2}{2 \times 9.8} = \frac{14^2}{19.6} = \frac{196}{19.6} = 10.0\text{ m} \).
