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Physics · JEE | Moving Charges and Magnetism

हिन्दी

A current-carrying circular coil of \( N \) turns and radius \( R \) produces magnetic field \( B_1 \) at its center. If the coil is unwound and rewound into a circular coil of radius \( \frac{R}{2} \) with the same number of turns carrying the same current, the new magnetic field \( B_2 \) at the center is:

  1. A
    \( 2 B_1 \)
  2. B
    \( 4 B_1 \)
  3. C
    \( \frac{B_1}{2} \)
  4. D
    \( \frac{B_1}{4} \)
View Answer & Solution

Correct answer · Option A

\( 2 B_1 \)

Explanation

Center field formula is \( B = \frac{\mu_0 N I}{2 R} \). Since radius is halved, field becomes twice, so \( B_2 = 2B_1 \).
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