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Physics · PYQ NEET UG 2026

हिन्दी

A current \( I_0 \) flows through a metallic circular loop of radius \( r \) as shown in the figure. Resistance of the segment \( ABC \) is half that of \( ADC \). Magnitude of magnetic field at the center \( O \) of the loop is :

Question diagram
  1. A
    \( \frac{\mu_0 I_0}{12r} \)
  2. B
    \( \frac{\mu_0 I_0}{4r} \)
  3. C
    \( \frac{\mu_0 I_0}{2r} \)
  4. D
    \( \frac{\mu_0 I_0}{2\pi r} \)
View Answer & Solution

Correct answer · Option B

\( \frac{\mu_0 I_0}{4r} \)

Explanation

Since resistance of \( ABC \) is half of \( ADC \), currents divide inversely proportional to resistances, producing magnetic fields that subtract to give \( \frac{\mu_0 I_0}{4r} \).
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