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Physics · PYQ NEET UG 2019(2)

हिन्दी

A cycle wheel of radius \( 0.5\text{ m} \) is rotated with constant angular velocity of \( 10\text{ rad/s} \) in a region of magnetic field of \( 0.1\text{ T} \) which is perpendicular to the plane of the wheel. The e.m.f. generated between its centre and the rim is,

  1. A
    Zero
  2. B
    0.25 V
  3. C
    0.125 V
  4. D
    0.5 V
View Answer & Solution

Correct answer · Option C

0.125 V

Explanation

Induced e.m.f. between center and rim of a rotating disc is given by \( e = \frac{1}{2} B \omega R^2 = \frac{1}{2} \times 0.1 \times 10 \times (0.5)^2 = 0.125\text{ V} \).
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