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Chemistry · Organic chemistry – some basic principles and techniques

हिन्दी

A high-boiling liquid decomposes at its normal boiling point of \( 563\text{ K} \) under \( 760\text{ mm Hg} \). If the external pressure is reduced to \( 10\text{ mm Hg} \) using a vacuum pump, the liquid boils at \( 453\text{ K} \). What is the vapour pressure of the liquid at this reduced boiling point of \( 453\text{ K} \)?

  1. A
    \( 760\text{ mm Hg} \)
  2. B
    \( 380\text{ mm Hg} \)
  3. C
    \( 0\text{ mm Hg} \)
  4. D
    \( 10\text{ mm Hg} \)
View Answer & Solution

Correct answer · Option D

\( 10\text{ mm Hg} \)

Explanation

A liquid boils when its saturated vapour pressure equals the external pressure: \( p_{\text{vap}} = p_{\text{ext}} \). Since \( p_{\text{ext}} = 10\text{ mm Hg} \), the vapour pressure at the boiling point is exactly \( 10\text{ mm Hg} \).
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