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Physics · MOTION IN A PLANE
हिन्दीA hiker stands at the edge of a cliff \( 490\text{ m} \) high above the ground and throws a stone horizontally with an initial speed of \( 15\text{ m/s} \). Taking \( g = 9.8\text{ m/s}^2 \), the time taken by the stone to reach the ground is:
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Correct answer · Option C
10 s
Explanation
Vertical motion: \( y = \frac{1}{2}gt^2 \implies 490 = \frac{1}{2}(9.8)t^2 \implies 4.9t^2 = 490 \implies t^2 = 100 \implies t = 10\text{ s} \).
