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Physics · PYQ NEET UG 2016(2)

हिन्दी

A light rod of length \( l \) has two masses \( m_1 \) and \( m_2 \) attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is

  1. A
    \( \sqrt{m_1 m_2} l^2 \)
  2. B
    \( \frac{m_1 m_2}{m_1 + m_2} l^2 \)
  3. C
    \( \frac{m_1 + m_2}{m_1 m_2} l^2 \)
  4. D
    \( (m_1 + m_2) l^2 \)
View Answer & Solution

Correct answer · Option B

\( \frac{m_1 m_2}{m_1 + m_2} l^2 \)

Explanation

Distances of masses from CM are \( r_1 = \frac{m_2 l}{m_1 + m_2} \) and \( r_2 = \frac{m_1 l}{m_1 + m_2} \). \( I = m_1 r_1^2 + m_2 r_2^2 = \frac{m_1 m_2}{m_1 + m_2} l^2 \).
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