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Physics · LAWS OF MOTION
हिन्दीA mass of \( 6\text{ kg} \) is suspended in equilibrium by a light rope of length \( 2\text{ m} \) hanging from a ceiling. A horizontal force of \( 50\text{ N} \) is applied at the midpoint P of the rope as shown in the figure. Taking \( g = 10\text{ m/s}^2 \), what is the tension in the upper segment of the rope?
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Correct answer · Option A
\( 10\sqrt{61}\text{ N} \)
Explanation
For the midpoint P: vertical tension component \( T_1 \cos\theta = W = 60\text{ N} \), horizontal tension component \( T_1 \sin\theta = 50\text{ N} \). Upper tension \( T_1 = \sqrt{(50)^2 + (60)^2} = \sqrt{2500 + 3600} = \sqrt{6100} = 10\sqrt{61}\text{ N} \).
