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Physics · JEE | Electromagnetic Induction

हिन्दी

A metallic rod of length \( l \) is rotated about one of its ends in a plane perpendicular to a uniform magnetic field \( B \) with an angular frequency \( \omega \). What is the induced emf across its ends?

  1. A
    \( \varepsilon = B \omega l^2 \)
  2. B
    \( \varepsilon = 2 B \omega l^2 \)
  3. C
    \( \varepsilon = \frac{1}{4} B \omega l^2 \)
  4. D
    \( \varepsilon = \frac{1}{2} B \omega l^2 \)
View Answer & Solution

Correct answer · Option D

\( \varepsilon = \frac{1}{2} B \omega l^2 \)

Explanation

Integrating motional emf along a rotating rod of length \( l \) gives \( \varepsilon = \frac{1}{2} B \omega l^2 \).
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