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Chemistry · PYQ NEET UG 2018

हिन्दी

A mixture of \( 2.3 \mathrm{~g} \) formic acid and \( 4.5 \mathrm{~g} \) oxalic acid is treated with conc. \( \mathrm{H}_{2} \mathrm{SO}_{4} \). The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

  1. A
    1.4
  2. B
    3.0
  3. C
    2.8
  4. D
    4.4
View Answer & Solution

Correct answer · Option A

1.4

Explanation

Formic acid gives CO and \( \mathrm{H}_2\mathrm{O} \); oxalic acid gives CO, \( \mathrm{CO}_2 \), and \( \mathrm{H}_2\mathrm{O} \) with conc. \( \mathrm{H}_2\mathrm{SO}_4 \). KOH absorbs \( \mathrm{CO}_2 \), leaving CO gas behind. \( 0.05 \) mol of CO has mass \( 0.05 \times 28 = 1.4 \mathrm{~g} \).
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