Physics · MOTION IN A STRAIGHT LINE
हिन्दीA moving vehicle with initial speed \( v_0 \) travels a stopping distance \( d_s \) under constant braking deceleration \( a \). If the initial speed of the vehicle is tripled to \( 3v_0 \) under the same deceleration, the new stopping distance will be:
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Correct answer · Option B
\( 9 d_s \)
Explanation
Stopping distance \( d_s = \frac{v_0^2}{2a} \propto v_0^2 \). Tripling the velocity increases the stopping distance by a factor of \( 3^2 = 9 \).