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Physics · PYQ NEET UG 2021
हिन्दीA nucleus with mass number \( 240 \) breaks into two fragments each of mass number \( 120 \), the binding energy per nucleon of fragmented nuclei is \( 7.6\text{ MeV} \) while that of fragments is \( 8.5\text{ MeV} \). The total gain in the Binding Energy in the process is:
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Correct answer · Option C
216 MeV
Explanation
Total Binding Energy initially = \( 240 \times 7.6\text{ MeV} \). Total Binding Energy finally = \( 2 \times 120 \times 8.5\text{ MeV} = 240 \times 8.5\text{ MeV} \). Gain = \( 240 \times (8.5 - 7.6) = 240 \times 0.9 = 216\text{ MeV} \).
