OnlineCBT Logo OnlineCBT

Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A particle moves along a straight line such that its position \( x \) at time \( t \) is given by \( x = t^3 - 6t^2 + 9t + 5 \). At what time(s) is the velocity of the particle zero?

  1. A
    \( t = 2\text{ s} \) and \( t = 4\text{ s} \)
  2. B
    \( t = 0\text{ s} \) only / केवल \( t = 0\text{ s} \)
  3. C
    \( t = 1\text{ s} \) and \( t = 3\text{ s} \)
  4. D
    \( t = 3\text{ s} \) only / केवल \( t = 3\text{ s} \)

Correct answer · Option C

\( t = 1\text{ s} \) and \( t = 3\text{ s} \)

Explanation

Velocity \( v = \frac{dx}{dt} = 3t^2 - 12t + 9 = 0 \Rightarrow t^2 - 4t + 3 = 0 \Rightarrow (t-1)(t-3) = 0 \), giving \( t = 1\text{ s} \) and \( t = 3\text{ s} \).
पता संपर्क करें

+91 7877547686

ई-मेल

onlinecbtportal@gmail.com

हेल्पलाइन नंबर

+91 7877547686


डाउनलोड करने के लिए क्लिक करें
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat