A population of diploid organisms is at Hardy-Weinberg equilibrium. If the frequency of allele A is 0.1, the frequency of AA is

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Correct answer · Option A

0.01

According to Hardy-Weinberg law, frequency of AA is $p^2$. Given $p = 0.1$, so $p^2 = (0.1)^2 = 0.01$.

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