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Physics · JEE | Moving Charges and Magnetism
हिन्दीA proton and an alpha particle with same kinetic energy enter perpendicularly into a uniform magnetic field \( B \). The ratio of their radii of circular paths \( r_p : r_\alpha \) is:
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Correct answer · Option B
\( 1 : \sqrt{2} \)
Explanation
Radius in magnetic field is \( r = \frac{\sqrt{2mK}}{qB} \). Substituting \( m_\alpha = 4m_p \) and \( q_\alpha = 2q_p \), we get \( r_p : r_\alpha = 1 : \sqrt{2} \).
