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Physics · PYQ NEET UG 2021

English

एक रेडियोएक्टिव नाभिक \( {}^A_Z X \), स्वतः क्षय श्रृंखला \( {}^A_Z X \rightarrow {}_{Z-1} B \rightarrow {}_{Z-3} C \rightarrow {}_{Z-2} D \) से गुजरता है, जहाँ \( Z \) तत्व \( X \) की परमाणु संख्या है। इस क्रम में संभावित क्षय कण हैं:

  1. A
    \( \alpha, \beta^+, \beta^- \)
  2. B
    \( \beta^+, \alpha, \beta^- \)
  3. C
    \( \beta^-, \alpha, \beta^+ \)
  4. D
    \( \alpha, \beta^-, \beta^+ \)
उत्तर और समाधान देखें

सही उत्तर · विकल्प B

\( \beta^+, \alpha, \beta^- \)

व्याख्या

Step 1: Analyze the first decay step from \( {}^A_Z X \) to \( {}_{Z-1} B \). The atomic number decreases by 1 (\( Z \rightarrow Z-1 \)), which corresponds to positron emission (\( \beta^+ \) decay).
Step 2: Analyze the second decay step from \( {}_{Z-1} B \) to \( {}_{Z-3} C \). The atomic number decreases by 2 (\( Z-1 \rightarrow Z-3 \)) and the mass number decreases by 4 (since it's a standard radioactive decay chain), which corresponds to an alpha (\( \alpha \)) particle emission.
Step 3: Analyze the third decay step from \( {}_{Z-3} C \) to \( {}_{Z-2} D \). The atomic number increases by 1 (\( Z-3 \rightarrow Z-2 \)), which corresponds to electron emission (\( \beta^- \) decay).
Step 4: Therefore, the sequence of decay particles is \( \beta^+, \alpha, \beta^- \).
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