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Chemistry · EQUILIBRIUM
हिन्दीA sample of soft drink has a hydrogen ion concentration of \( 3.8 \times 10^{-3}\text{ M} \). If \( \log 3.8 = 0.58 \), what is the \( \text{pOH} \) of this soft drink at \( 298\text{ K} \)?
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Correct answer · Option B
11.58
Explanation
\( \text{pH} = -\log(3.8 \times 10^{-3}) = 3 - 0.58 = 2.42 \). Since \( \text{pH} + \text{pOH} = 14 \), \( \text{pOH} = 14 - 2.42 = 11.58 \).
