OnlineCBT
Physics · PYQ NEET UG 2023
हिन्दीA satellite is orbiting just above the surface of the earth with period \( T \). If \( d \) is the density of the earth and \( G \) is the universal constant of gravitation, the quantity \( \frac{3\pi}{Gd} \) represents :
View Answer & Solution
Correct answer · Option A
\( T^2 \)
Explanation
Orbital period near surface \( T = 2\pi \sqrt{\frac{R}{g}} \). Since \( g = \frac{4}{3}\pi G d R \), substituting \( g \) gives \( T = \sqrt{\frac{3\pi}{Gd}} \), so \( \frac{3\pi}{Gd} = T^2 \).
