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Physics · JEE | Electromagnetic Induction
हिन्दीA square loop of side \( 10\text{ cm} \) and resistance \( 0.5\ \Omega \) is placed in a uniform magnetic field of \( 0.10\text{ T} \) directed at \( 45^\circ \) to the area vector. If the field is reduced to zero in \( 0.70\text{ s} \), the magnitude of the induced current is approximately:
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Correct answer · Option C
\( 2.0\text{ mA} \)
Explanation
Initial flux \( \Phi = B A \cos 45^\circ \). Using \( \varepsilon = \frac{\Delta\Phi}{\Delta t} \) and \( I = \frac{\varepsilon}{R} \), we get \( I = 2\text{ mA} \).
