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Physics · JEE | WAVES

हिन्दी

A standing wave on a string of length \( L \) fixed at both ends is represented by \( y(x, t) = 2a \sin(kx) \cos(\omega t) \). The positions of nodes along the string are given by:

  1. A
    \( x = (n + \frac{1}{2})\frac{\lambda}{2}, \quad n = 0, 1, 2, 3, \dots \)
  2. B
    \( x = \frac{n\lambda}{2}, \quad n = 0, 1, 2, 3, \dots \)
  3. C
    \( x = n\lambda, \quad n = 1, 2, 3, \dots \)
  4. D
    \( x = (n + \frac{1}{4})\frac{\lambda}{2}, \quad n = 0, 1, 2, \dots \)
View Answer & Solution

Correct answer · Option B

\( x = \frac{n\lambda}{2}, \quad n = 0, 1, 2, 3, \dots \)

Explanation

Nodes occur where the amplitude is zero, i.e., \( \sin(kx) = 0 \implies kx = n\pi \implies x = \frac{n\lambda}{2} \).
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