Physics · LAWS OF MOTION
हिन्दीA stone of mass \( 0.2 \text{ kg} \) tied to the end of a string is whirled in a horizontal circle of radius \( 0.5 \text{ m} \) with a constant speed of \( 4 \text{ m s}^{-1} \). The tension force provided by the string is:
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Correct answer · Option A
\( 6.4 \text{ N} \)
Explanation
The horizontal centripetal force is supplied by string tension: \( F = \frac{m v^2}{r} = \frac{0.2 \times 4^2}{0.5} = 6.4 \text{ N} \).