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Physics · UNITS AND MEASUREMENT

हिन्दी

A substance of mass \( 5.74 \text{ g} \) occupies a volume of \( 1.2 \text{ cm}^3 \). Express its density to the correct number of significant figures, and identify the underlying rule.

  1. A
    \( 4.8 \text{ g cm}^{-3} \), as the result should retain as many significant figures as the input quantity with the least significant figures.
  2. B
    \( 4.78 \text{ g cm}^{-3} \), as the result should retain as many significant figures as the input quantity with the maximum significant figures.
  3. C
    \( 4.783 \text{ g cm}^{-3} \), as arithmetic division allows up to 4 significant figures.
  4. D
    \( 5.0 \text{ g cm}^{-3} \), after rounding off to the nearest integer.
View Answer & Solution

Correct answer · Option A

\( 4.8 \text{ g cm}^{-3} \), as the result should retain as many significant figures as the input quantity with the least significant figures.

Explanation

Density = \( \frac{5.74 \text{ g}}{1.2 \text{ cm}^3} = 4.7833... \text{ g cm}^{-3} \). Mass has 3 significant figures and volume has 2 significant figures. In division, the final answer must retain 2 significant figures (the minimum of the input values), so density = \( 4.8 \text{ g cm}^{-3} \).
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