OnlineCBT
Physics · PYQ NEET UG 2016(1)
हिन्दीA uniform circular disc of radius \( 50\text{ cm} \) at rest is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of \( 2.0\text{ rad s}^{-2} \). Its net acceleration in \( \text{ms}^{-2} \) at the end of \( 2.0\text{ s} \) is approximately
View Answer & Solution
Correct answer · Option C
\( 8.0 \)
Explanation
At \( t = 2\text{ s} \), angular velocity \( \omega = \alpha t = 2 \times 2 = 4\text{ rad/s} \). Tangential acceleration \( a_t = r \alpha = 0.5 \times 2 = 1\text{ m/s}^2 \). Centripetal acceleration \( a_c = \omega^2 r = 4^2 \times 0.5 = 8\text{ m/s}^2 \). Net acceleration \( a = \sqrt{a_t^2 + a_c^2} = \sqrt{1^2 + 8^2} = \sqrt{65} \approx 8.0\text{ m/s}^2 \).
