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Chemistry · EQUILIBRIUM
हिन्दीA weak monobasic acid has an ionization constant \( K_a = 1.74 \times 10^{-5} \). What is its \( \text{p}K_a \)? (Given: \( \log 1.74 = 0.24 \))
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Correct answer · Option C
4.76
Explanation
\( \text{p}K_a = -\log(K_a) = -\log(1.74 \times 10^{-5}) = 5 - 0.24 = 4.76 \).
