Physics · LAWS OF MOTION

A wooden block of mass \( m_1 = 3\text{ kg} \) rests on a soft horizontal floor. An iron cylinder of mass \( m_2 = 17\text{ kg} \) is placed on top of the block. The floor yields steadily, causing the block-cylinder system to accelerate downwards at \( a = 2\text{ m/s}^2 \). Taking \( g = 10\text{ m/s}^2 \), calculate (i) the normal action force exerted by the block on the floor, and (ii) the normal reaction force exerted by the cylinder on the block.

1. A
   \( 200\text{ N} \) and \( 170\text{ N} \)
2. B
   \( 160\text{ N} \) and \( 136\text{ N} \)
3. C
   \( 160\text{ N} \) and \( 24\text{ N} \)
4. D
   \( 240\text{ N} \) and \( 204\text{ N} \)