OnlineCBT
Physics · JEE | Alternating Current
हिन्दीAn alternating voltage given by \( v = 282 \sin(314 t) \) is connected across a pure resistor of \( 50\ \Omega \). What is the rms value of the current flowing through the resistor?
View Answer & Solution
Correct answer · Option B
\( 4.0\text{ A} \)
Explanation
The peak voltage is \( v_m = 282\text{ V} \), so rms voltage is \( V = \frac{v_m}{\sqrt{2}} \approx 200\text{ V} \). The rms current is \( I = \frac{V}{R} = \frac{200}{50} = 4.0\text{ A} \).
