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Physics · Electrostatic Potential

हिन्दी

An electric dipole of dipole moment \( p = 2 \times 10^{-8}\text{ C m} \) is placed in an electric field. At a point \( r = 1\text{ m} \) along the axis of the dipole, what is the magnitude of the electrostatic potential? (\( \frac{1}{4\pi\varepsilon_0} = 9 \times 10^9\text{ N m}^2\text{ C}^{-2} \))

  1. A
    \( 180\text{ V} \)
  2. B
    \( 90\text{ V} \)
  3. C
    \( 360\text{ V} \)
  4. D
    \( 720\text{ V} \)
View Answer & Solution

Correct answer · Option A

\( 180\text{ V} \)

Explanation

\( V = \frac{1}{4\pi\varepsilon_0} \frac{p}{r^2} = \frac{9 \times 10^9 \times 2 \times 10^{-8}}{1^2} = 180\text{ V} \).
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