Physics · JEE | Electric Charges and Fields
हिन्दीAn electron falls through a distance of \( 1.5\text{ cm} \) in a uniform electric field of magnitude \( 2.0 \times 10^4\text{ N/C} \). The time of fall starting from rest is approximately:
View Answer & Solution
Correct answer · Option B
\( 2.9 \times 10^{-9}\text{ s} \)
Explanation
Acceleration \( a = \frac{eE}{m} \). Distance \( s = \frac{1}{2}at^2 \Rightarrow t = \sqrt{\frac{2ms}{eE}} \approx 2.9 \times 10^{-9}\text{ s} \).