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Physics · PYQ NEET UG 2019(1)
हिन्दीAn electron is accelerated through a potential difference of \( 10,000\text{ V} \). Its de Broglie wavelength is, (nearly) (\( m_e = 9 \times 10^{-31}\text{ kg} \))
Correct answer · Option D
\( 12.2 \times 10^{-12}\text{ m} \)
Explanation
de Broglie wavelength \( \lambda = \frac{12.27}{\sqrt{V}}\text{ \AA} = \frac{12.27}{\sqrt{10000}}\text{ \AA} = 0.1227\text{ \AA} = 12.2 \times 10^{-12}\text{ m} \).
