An inductor \( 20 \text{ mH} \), a capacitor \( 100 \mu\text{F} \) and a resistor \( 50 \Omega \) are connected in series across a source of emf, \( V = 10 \sin 314 t \). The power loss in the circuit is

Here \( \omega = 314 \text{ rad/s} \). Inductive reactance \( X_L = \omega L = 314 \times 20 \times 10^{-3} = 6.28 \Omega \). Capacitive reactance \( X_C = \frac{1}{\omega C} = \frac{1}{314 \times 100 \times 10^{-6}} \approx 31.8 \Omega \). Impedance \( Z = \sqrt{R^2 + (X_C - X_L)^2} \). Power loss \( P = \frac{V_{rms}^2 R}{Z^2} \) which evaluates to approximately \( 0.79 \text{ W} \).