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Physics · PYQ NEET UG 2019(2)

हिन्दी

An LED is constructed from a p-n junction diode using GaAsP. The energy gap is \( 1.9\text{ eV} \). The wavelength of the light emitted will be equal to

  1. A
    \( 654 \times 10^{-11}\text{ m} \)
  2. B
    \( 10.4 \times 10^{-26}\text{ m} \)
  3. C
    \( 654\text{ nm} \)
  4. D
    \( 654\text{ Å} \)
View Answer & Solution

Correct answer · Option C

\( 654\text{ nm} \)

Explanation

Using \( \lambda = \frac{hc}{E} = \frac{12400\text{ eV}\cdot\text{Å}}{1.9\text{ eV}} \approx 6526\text{ Å} = 652.6\text{ nm} \approx 654\text{ nm} \).
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