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Physics · JEE | MOTION IN A STRAIGHT LINE

हिन्दी

An object in free fall starts from rest at \( y = 0 \). What is its velocity after falling through a distance of \( 19.6\text{ m} \)? (Assume \( g = 9.8\text{ m s}^{-2} \))

  1. A
    \( -9.8 m s$^{-1}$ \)
  2. B
    \( -14.7 m s$^{-1}$ \)
  3. C
    \( -39.2 m s$^{-1}$ \)
  4. D
    \( -19.6 m s$^{-1}$ \)
View Answer & Solution

Correct answer · Option D

\( -19.6 m s$^{-1}$ \)

Explanation

Using \( v^2 = v_0^2 - 2gy = 0 - 2(9.8)(19.6) = -384.16 \), so \( v = -\sqrt{384.16} = -19.6\text{ m s}^{-1} \).
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