Physics · JEE | MOTION IN A STRAIGHT LINE
हिन्दीAn object in free fall starts from rest at \( y = 0 \). What is its velocity after falling through a distance of \( 19.6\text{ m} \)? (Assume \( g = 9.8\text{ m s}^{-2} \))
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Correct answer · Option D
\( -19.6 m s$^{-1}$ \)
Explanation
Using \( v^2 = v_0^2 - 2gy = 0 - 2(9.8)(19.6) = -384.16 \), so \( v = -\sqrt{384.16} = -19.6\text{ m s}^{-1} \).