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Physics · Electrostatic Potential
हिन्दीAn uncharged capacitor of capacitance \( C \) is connected across a battery of EMF \( V \). During the charging process, the total energy supplied by the battery is \( W_b \) and the electrostatic energy stored in the capacitor is \( U \). The ratio \( \frac{U}{W_b} \) is:
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Correct answer · Option D
\( \frac{1}{2} \)
Explanation
Work done by battery is \( W_b = Q V = C V^2 \). Energy stored in capacitor is \( U = \frac{1}{2} C V^2 \). Hence, \( \frac{U}{W_b} = \frac{1}{2} \).
