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Physics · MECHANICAL PROPERTIES OF SOLIDS

हिन्दी

At an ocean trench of depth \( h \), the density of sea water at the surface is \( 1.00 \times 10^3\text{ kg m}^{-3} \). If the bulk modulus of water is \( 2.0 \times 10^9\text{ N m}^{-2} \) and the fractional compression \( \Delta V / V \) at the bottom is found to be \( 2.0\% \), the depth \( h \) of the trench (taking \( g = 10\text{ m s}^{-2} \) and assuming density variation is negligible for calculating hydrostatic pressure) is:

  1. A
    \( 1000\text{ m} \)
  2. B
    \( 2000\text{ m} \)
  3. C
    \( 3000\text{ m} \)
  4. D
    \( 4000\text{ m} \)
View Answer & Solution

Correct answer · Option D

\( 4000\text{ m} \)

Explanation

\( p = B (\frac{-\Delta V}{V}) = 2.0 \times 10^9 \times 0.02 = 4.0 \times 10^7\text{ N m}^{-2} \). Since \( p = h \rho g \), \( h = \frac{4.0 \times 10^7}{10^3 \times 10} = 4000\text{ m} \).
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