Physics · MECHANICAL PROPERTIES OF SOLIDS
हिन्दीAt an ocean trench of depth \( h \), the density of sea water at the surface is \( 1.00 \times 10^3\text{ kg m}^{-3} \). If the bulk modulus of water is \( 2.0 \times 10^9\text{ N m}^{-2} \) and the fractional compression \( \Delta V / V \) at the bottom is found to be \( 2.0\% \), the depth \( h \) of the trench (taking \( g = 10\text{ m s}^{-2} \) and assuming density variation is negligible for calculating hydrostatic pressure) is:
View Answer & Solution
Correct answer · Option D
\( 4000\text{ m} \)
Explanation
\( p = B (\frac{-\Delta V}{V}) = 2.0 \times 10^9 \times 0.02 = 4.0 \times 10^7\text{ N m}^{-2} \). Since \( p = h \rho g \), \( h = \frac{4.0 \times 10^7}{10^3 \times 10} = 4000\text{ m} \).