Physics · GRAVITATION
हिन्दीAt what height \( h \) above the surface of the Earth does the acceleration due to gravity become \( \frac{g}{9} \), where \( g \) is the value of acceleration due to gravity on the Earth's surface and \( R_E \) is the Earth's radius?
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Correct answer · Option A
\( h = 2R_E \)
Explanation
Using \( g(h) = \frac{g}{(1 + \frac{h}{R_E})^2} = \frac{g}{9} \), we get \( 1 + \frac{h}{R_E} = 3 \implies h = 2R_E \).