Physics · JEE | Electric Charges and Fields
हिन्दीBased on Figure 1.11 depicting two point charges \( q_1 = +10^{-8} \text{ C} \) and \( q_2 = -10^{-8} \text{ C} \) separated by \( 0.1 \text{ m} \), what is the magnitude of the electric field at point C situated at equal distance \( 0.1 \text{ m} \) from both charges?
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Correct answer · Option C
\( 9 \times 10^3 \text{ N C}^{-1} \)
Explanation
Using \( E = \frac{1}{4\pi\varepsilon_0}\frac{q}{r^2} = \frac{9 \times 10^9 \times 10^{-8}}{(0.10)^2} = 9 \times 10^3 \text{ N C}^{-1} \).