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Physics · JEE | Electric Charges and Fields

हिन्दी

Based on Figure 1.11 depicting two point charges \( q_1 = +10^{-8} \text{ C} \) and \( q_2 = -10^{-8} \text{ C} \) separated by \( 0.1 \text{ m} \), what is the magnitude of the electric field at point C situated at equal distance \( 0.1 \text{ m} \) from both charges?

Question diagram
  1. A
    \( 7.2 \times 10^4 \text{ N C}^{-1} \)
  2. B
    \( 3.6 \times 10^4 \text{ N C}^{-1} \)
  3. C
    \( 9 \times 10^3 \text{ N C}^{-1} \)
  4. D
    \( 4 \times 10^3 \text{ N C}^{-1} \)
View Answer & Solution

Correct answer · Option C

\( 9 \times 10^3 \text{ N C}^{-1} \)

Explanation

Using \( E = \frac{1}{4\pi\varepsilon_0}\frac{q}{r^2} = \frac{9 \times 10^9 \times 10^{-8}}{(0.10)^2} = 9 \times 10^3 \text{ N C}^{-1} \).
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