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Physics · JEE | WORK, ENERGY AND POWER

हिन्दी

Based on the parabolic plots of potential energy \( V \) and kinetic energy \( K \) of a block attached to a spring obeying Hooke's law (shown in the chapter), what happens to the total mechanical energy \( E = K + V \) as the block oscillates between \( -x_m \) and \( +x_m \)?

Question diagram
  1. A
    It continuously increases from \( -x_m \) to \( +x_m \).
  2. B
    It remains constant at all points.
  3. C
    It is zero at the equilibrium position \( x = 0 \).
  4. D
    It equals kinetic energy only at the turning points.
View Answer & Solution

Correct answer · Option B

It remains constant at all points.

Explanation

The total mechanical energy \( E = K + V \) remains constant throughout the motion, as depicted by the horizontal line in Fig. 5.8.
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