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Mathematics · JEE | LIMITS AND DERIVATIVES
हिन्दीCalculate the average velocity in the first 2 seconds for a freely falling body with distance formula \( s = 4.9 t^2 \).
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Correct answer · Option B
9.8 m/s
Explanation
Average velocity between \( t_1 = 0 \) and \( t_2 = 2 \) is \( \frac{s(2) - s(0)}{2 - 0} = \frac{19.6 - 0}{2} = 9.8 \) m/s.
