Chemistry · JEE | Thermodynamics (Chemical Thermodynamics)
हिन्दीCalculate the standard Gibbs energy change (\( \Delta_r G^\ominus \) ) for the conversion of oxygen to ozone, \( \frac{3}{2}\text{O}_2(g) \rightarrow \text{O}_3(g) \) at \( 298 \text{ K} \), given that the equilibrium constant \( K_p = 2.47 \times 10^{-29} \) and \( R = 8.314 \text{ J K}^{-1} \text{ mol}^{-1} \).
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Correct answer · Option B
+163 kJ mol⁻¹
Explanation
Using \( \Delta_r G^\ominus = -2.303 RT \log K_p = -2.303 \times 8.314 \times 298 \times \log(2.47 \times 10^{-29}) = +163000 \text{ J mol}^{-1} = +163 \text{ kJ mol}^{-1} \).